Practice portal › Rotational Motion › Moment of Force and Torque
Asked in CBSE AIPMT 1995 · Torque and moment of a force
Given: ⃗F=2̂i-3̂j+4̂k N at ⃗r=3̂i+2̂j+3̂k m.
Idea: τ⃗=⃗r×⃗F, with the position vector first.
̂i: r_yF_z-r_zF_y=(2)(4)-(3)(-3)=8+9=17
̂j: r_zFₓ-rₓF_z=(3)(2)-(3)(4)=6-12=-6
̂k: rₓF_y-r_yFₓ=(3)(-3)-(2)(2)=-9-4=-13
τ⃗=17̂i-6̂j-13̂k N m
Reading this solution needs no sign-in. You only sign in to practise against the clock and keep your progress.
Practise this with a timer