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Asked in NEET 2020 · Torque and moment of a force
Given: ⃗F=3̂j N at ⃗r=2̂k m.
Idea: torque about the origin is τ⃗=⃗r×⃗F.
τ⃗=(2̂k)×(3̂j)=6 (̂k×̂j)
The cyclic order is ̂i×̂j=̂k, ̂j×̂k=̂i, ̂k×̂i=̂j, so ̂k×̂j=-̂i.
τ⃗=-6̂i N m
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