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The phase difference between the displacement and the acceleration of a particle in simple harmonic motion is:

Asked in NEET 2020 · v-x and a-x relations

Answer: (4) π rad

Step-by-step solution

Given: x=A sin ω t.

Idea: differentiate twice and compare the two sinusoids.

v=(dx)/(dt)=Aω cos ω t

a=(dv)/(dt)=-Aω² sin ω t

a=Aω² sin(ω t+π)

So the acceleration is the displacement turned through half a cycle: the phase difference is π rad.

Why the other options are wrong

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