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The distance covered by a particle undergoing SHM in one time period is (amplitude =A)

Asked in Odisha NEET 2019 · Time, distance and displacement

Answer: (4) 4A

Step-by-step solution

Idea: follow the path over one full period and add the four legs.

Mean position to one extreme: A.

Back to the mean position: another A.

On to the opposite extreme: another A.

Back to the mean position: another A.

Total distance =4A

Why the other options are wrong

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