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Asked in AIPMT 2005 · Dipole in a uniform field
Given: one triangular turn of side l carrying current i, with ⃗B lying in the plane of the coil.
Idea: τ=iAB sin θ with θ the angle between the normal and ⃗B.
If ⃗B is in the plane of the coil, the normal is perpendicular to it, so θ=90° and sin θ=1.
Area of an equilateral triangle: A=(√3)/4l².
So τ=i (√3)/4l² B.
Rearranging: l²=(4τ)/(√3 Bi).
Taking the root: l=2(τ/(√3 Bi))^1/2.
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