Practice portal › Mechanical Properties of Fluids › Continuity and Bernoulli's Theorem
Asked in RE-NEET 2026 · Venturimeter and flow measurement
Given: A_P=40 cm², A_Q=20 cm², P_P-P_Q=15 N m⁻², ρ=1000 kg m⁻³.
Idea: continuity fixes the ratio of the speeds and Bernoulli then converts the pressure drop into that speed difference.
Continuity: A_Pv_P=A_Qv_Q, so 40v_P=20v_Q and v_Q=2v_P.
Bernoulli on a horizontal pipe: P_P-P_Q=1/2ρ(v_Q²-v_P²)
15=1/2×1000×(4v_P²-v_P²)=1500 v_P²
v_P²=0.01, so v_P=0.1 m s⁻¹.
Q=A_Pv_P=40×10⁻⁴×0.1=4×10⁻⁴ m³ s⁻¹
4×10⁻⁴ m³ s⁻¹=400 cm³ s⁻¹
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