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Water flows in a streamline motion through a horizontal pipe of circular cross-section as shown in the figure. The pressure difference of water between P and Q is 15 N m⁻². The areas of cross-section at P and Q are 40 cm² and 20 cm² respectively. The rate of flow of water through the pipe, in cm³ s⁻¹, is: [Take density of water =1000 kg m⁻³]

Asked in RE-NEET 2026 · Venturimeter and flow measurement

Figure: Venturimeter and flow measurement
Answer: (1) 400

Step-by-step solution

Given: A_P=40 cm², A_Q=20 cm², P_P-P_Q=15 N m⁻², ρ=1000 kg m⁻³.

Idea: continuity fixes the ratio of the speeds and Bernoulli then converts the pressure drop into that speed difference.

Continuity: A_Pv_P=A_Qv_Q, so 40v_P=20v_Q and v_Q=2v_P.

Bernoulli on a horizontal pipe: P_P-P_Q=1/2ρ(v_Q²-v_P²)

15=1/2×1000×(4v_P²-v_P²)=1500 v_P²

v_P²=0.01, so v_P=0.1 m s⁻¹.

Q=A_Pv_P=40×10⁻⁴×0.1=4×10⁻⁴ m³ s⁻¹

4×10⁻⁴ m³ s⁻¹=400 cm³ s⁻¹

Why the other options are wrong

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