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A block of mass 10 kg is placed on a rough horizontal surface having coefficient of friction μ=0.5. If a horizontal force of 100 N is acting on it, then the acceleration of the block will be

Asked in AIPMT 2002 · Friction on a level surface

Answer: (2) 5 m/s²

Step-by-step solution

Given: m=10 kg, μ=0.5, F=100 N, g=10 m/s².

Idea: friction acts backwards along the surface, so subtract it from the applied force.

Normal force: N=mg=10×10=100 N.

Friction: f=μ N=0.5×100=50 N.

Net force: 100-50=50 N.

a=(50)/(10)=5 m/s².

Why the other options are wrong

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