Practice portal › Laws of Motion › Friction: Blocks, Belts and Inclines
Asked in AIPMT 2001 · Friction on belts and accelerating surfaces
Given: m=1 kg on a truck accelerating at 5 m/s²; μ=0.6.
Idea: static friction is a "supply on demand" force — it takes whatever value keeps the block moving with the truck, up to its own limit.
Friction needed to carry the block along: f=ma=1×5=5 N.
Greatest friction available: fₘₐₓ=μ mg=0.6×1×9.8=5.88 N.
Since 5<5.88, the block does not slip.
So the friction acting is exactly what is required: 5 N.
The 5.88 N is the ceiling, not the reading.
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