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The effective capacitances of two capacitors are 3 μF and 16 μF, when they are connected in series and parallel respectively. The capacitance of two capacitors are:

Asked in Re-NEET 2022 · Series and parallel combinations

Answer: (4) 12 μF, 4 μF

Step-by-step solution

C₁+C₂=16 and (C₁C₂)/(C₁+C₂)=3, so C₁C₂=48.

(C₁-C₂)²=16²-4×48=64, so C₁-C₂=8.

C₁=12 μF, C₂=4 μF.

Why the other options are wrong

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