Practice portal › Electric Potential and Capacitance › Capacitor Circuits and Energy

Two metallic spheres of radii 1 cm and 3 cm are given charges of -1×10⁻² C and 5×10⁻² C, respectively. If these are connected by a conducting wire, the final charge on the bigger sphere is

Asked in CBSE AIPMT 2012 Mains · Redistribution of charge

Answer: (2) 3×10⁻² C

Step-by-step solution

Total charge: -1×10⁻²+5×10⁻²=4×10⁻² C, and it is conserved.

Joined by a wire, both spheres reach the same potential: (kq₁)/(r₁)=(kq₂)/(r₂), so q∝ r.

Ratio 1:3, so the bigger sphere takes 3/4 of the total.

q₂=3/4×4×10⁻²=3×10⁻² C.

Why the other options are wrong

More Capacitor Circuits and Energy questionsAll Capacitor Circuits and Energy questions →

Reading this solution needs no sign-in. You only sign in to practise against the clock and keep your progress.

Practise this with a timer