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Asked in CBSE AIPMT 2012 Mains · Redistribution of charge
Total charge: -1×10⁻²+5×10⁻²=4×10⁻² C, and it is conserved.
Joined by a wire, both spheres reach the same potential: (kq₁)/(r₁)=(kq₂)/(r₂), so q∝ r.
Ratio 1:3, so the bigger sphere takes 3/4 of the total.
q₂=3/4×4×10⁻²=3×10⁻² C.
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