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A thin spherical shell is charged by some source. The potential difference between the two points C and P (in V) shown in the figure is: (Take 1/(4πε₀)=9×10⁹ SI units)

Asked in NEET 2024 · Potential of shells and spheres

Figure: Potential of shells and spheres
Answer: (2) Zero

Step-by-step solution

The field inside a uniformly charged thin shell is zero, so the potential is the same at every point inside it and on it: V=(kq)/R.

C is the centre and P is on the shell, so both are at (kq)/R=(9×10⁹×10⁻⁶)/(0.03)=3×10⁵ V.

V_C-V_P=0.

Why the other options are wrong

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