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Asked in CBSE AIPMT 2011 Mains · Work done in moving a charge
W=Q(V_E-V_D).
Because BC=AC, the triangle is symmetric about the line through C perpendicular to AB; the reflection swaps A and B and swaps D (midpoint of BC) with E (midpoint of CA).
D: B and C at distance a, and A at distance AD.
E: C and A at distance a, and B at distance BE; by the symmetry BE=AD.
So V_D=V_E and W=0.
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