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Charges +q and -q are placed at points A and B respectively which are a distance 2L apart, C is the midpoint between A and B. The work done in moving a charge +Q along the semicircle CRD is

Asked in CBSE AIPMT 2007 · Work done in moving a charge

Figure: Work done in moving a charge
Answer: (3) -(qQ)/(6πε₀ L)

Step-by-step solution

The semicircle is centred at B with radius BC=L, so D is a distance L beyond B: AD=3L, BD=L.

V_C=1/(4πε₀)(q/L-q/L)=0.

V_D=1/(4πε₀)(q/(3L)-q/L)=-(2q)/(3·4πε₀ L)=-q/(6πε₀ L).

Work by the external agent: W=Q(V_D-V_C)=-(qQ)/(6πε₀ L).

Why the other options are wrong

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