Practice portal › Electromagnetic Induction › Magnetic Flux
Asked in NEET 2008 · Flux through a surface
φ=BA cos θ, where θ is the angle between ⃗B and the normal to the disc.
The axis of the disc is itself the normal to the disc, so θ=60° and cos θ=1/2.
A=π r²=π×(0.2)²=0.04π m².
φ=1/π×0.04π×1/2=0.04×1/2=0.02 Wb.
The π in the field was chosen to cancel the π in the area.
Reading this solution needs no sign-in. You only sign in to practise against the clock and keep your progress.
Practise this with a timer