A square loop of side 1 m and resistance 1 Ω is placed in a magnetic field of 0.5 T. If the plane of the loop is perpendicular to the direction of the magnetic field, the magnetic flux through the loop is

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(2) 0.5 weber. The flux is φ=BA cos θ, where θ is the angle between the field and the normal to the loop. The plane of the loop is perpendicular to the field, so the normal is parallel to it and θ=0, giving cos θ=1. φ=0.5×1×1=0.5 Wb. The resistance is a distractor: it would matter for the induced current, but not for the flux.

A square loop of side 1 m and resistance 1 Ω is placed in a magnetic field of 0.5 T. If the plane of the loop is perpendicular to the direction of the magnetic field, the magnetic flux through the loop is

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