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Monochromatic light of frequency 6.0×10¹⁴ Hz is produced by a laser. The power emitted is 2×10⁻³ W. The number of photons emitted, on the average, by the source per second is:

Asked in AIPMT 2007 · Counting photons

Answer: (4) 5×10¹⁵

Step-by-step solution

Energy of one photon: E=h u=6.63×10⁻³⁴×6.0×10¹⁴.

E=3.98×10⁻¹⁹ J.

The laser delivers P=2×10⁻³ J each second, and P=NE.

N=(2×10⁻³)/(3.98×10⁻¹⁹)=5×10¹⁵ photons per second.

Why the other options are wrong

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