Practice portal › Dual Nature of Matter and Radiation › Photon Energy, Number of Photons and Intensity
Asked in AIPMT 2007 · Intensity, area and distance
The number of photoelectrons per second follows the intensity of the light at the surface.
For a point source, I=P/(4π d²), so I∝1/(d²).
Doubling the distance from 0.5 m to 1.0 m gives (I₁)/(I₂)=((1.0)/(0.5))²=4.
So the intensity, and with it the number of photoelectrons, falls by a factor of 4.
Neither the 5 W nor the wavelength is needed: the factor depends only on the distance ratio.
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