Practice portal › Dual Nature of Matter and Radiation › de Broglie Wavelength and Accelerating Potential
Asked in AIPMT 2011 · Accelerated through a potential difference
For an electron accelerated from rest through V: λ=h/(√2mₑ e V), so λ∝1/(√V).
The voltage goes from 25 kV to 100 kV, a factor of 4.
(λ₁)/(λ₂)=√(V₂)/(V₁)=√(100)/(25)=2.
So λ₂=(λ₁)/2: the wavelength decreases by a factor of 2.
That is why electron microscopes run at high voltage — a shorter wavelength resolves finer detail.
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