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Electrons used in an electron microscope are accelerated by a voltage of 25 kV. If the voltage is increased to 100 kV, then the de Broglie wavelength associated with the electrons would:

Asked in AIPMT 2011 · Accelerated through a potential difference

Answer: (2) decrease by 2 times

Step-by-step solution

For an electron accelerated from rest through V: λ=h/(√2mₑ e V), so λ∝1/(√V).

The voltage goes from 25 kV to 100 kV, a factor of 4.

(λ₁)/(λ₂)=√(V₂)/(V₁)=√(100)/(25)=2.

So λ₂=(λ₁)/2: the wavelength decreases by a factor of 2.

That is why electron microscopes run at high voltage — a shorter wavelength resolves finer detail.

Why the other options are wrong

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