Practice portal › Dual Nature of Matter and Radiation › de Broglie Wavelength and Accelerating Potential
Asked in AIPMT 1999 · Accelerated through a potential difference
A charge q falling through a potential difference V gains kinetic energy qV.
A proton carries q=+e, so it gains eV.
With V=1 V that is 1.6×10⁻¹⁹ J.
One electron-volt is defined as exactly this amount, so the kinetic energy is 1 eV.
The result is the same for any singly charged particle: an electron through 1 V also gains 1 eV.
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