An electron is accelerated from rest through a potential difference of V volt. If the de Broglie wavelength of the electron is 1.227×10⁻² nm, the potential difference is:

Question

Accepted Answer

(3) 10⁴ V. For an electron accelerated from rest through V volts, λ=(12.27)/(√V) ångström, that is λ=(12.27×10⁻¹⁰)/(√V) m. The given wavelength in metres: 1.227×10⁻² nm=1.227×10⁻¹¹ m. Rearranging: √V=(12.27×10⁻¹⁰)/(1.227×10⁻¹¹)=100. Squaring: V=10⁴ V.

An electron is accelerated from rest through a potential difference of V volt. If the de Broglie wavelength of the electron is 1.227×10⁻² nm, the potential difference is:

Step-by-step solution

Why the other options are wrong