A wire of resistance R is cut into 8 equal pieces. From these pieces two equivalent resistances are made by adding four of these together in parallel. Then these two sets are added in series. The net effective resistance of the combination is:

Question

Accepted Answer

(3) R/(16). Each piece: R/8. Four in parallel: (R/8)/4=R/(32). Two such sets in series: 2×R/(32)=R/(16).

A wire of resistance R is cut into 8 equal pieces. From these pieces two equivalent resistances are made by adding four of these together in parallel. Then these two sets are added in series. The net effective resistance of the combination is:

Step-by-step solution

Why the other options are wrong