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10 resistors, each of resistance R are connected in series to a battery of emf E and negligible internal resistance. Then those are connected in parallel to the same battery, the current is increased n times. The value of n is

Asked in NEET 2023 · Series and parallel combinations

Answer: (2) 100

Step-by-step solution

Series: Rₛ=10R, Iₛ=E/(10R).

Parallel: Rₚ=R/(10), Iₚ=(10E)/R.

n=(Iₚ)/(Iₛ)=(10R)/(R/10)=100.

Why the other options are wrong

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