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Asked in NEET 2024 · Rated bulbs and appliances
At the rated voltage V: R_A=(V²)/(1000) and R_B=(V²)/(2000), so R_A=2R_B.
Series: Pₛ=(V²)/(R_A+R_B)=(V²)/(3R_B).
Parallel: Pₚ=1+2=3 kW =(V²)/(R_A)+(V²)/(R_B)=(3V²)/(2R_B).
(Pₛ)/(Pₚ)=(1/3)/(3/2)=2/9.
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