Practice portal › Current Electricity › Combination of Resistors
Asked in CBSE AIPMT 1994 · Symmetric and complex networks
Reduce the network from the far corner F towards B.
A→ F→ E: 3+3=6 Ω, in parallel with AE=6 Ω: 3 Ω between A and E.
Add ED=3 Ω: 6 Ω, in parallel with AD=6 Ω: 3 Ω between A and D.
Add DC=3 Ω: 6 Ω, in parallel with AC=6 Ω: 3 Ω between A and C.
Add CB=3 Ω: 6 Ω, in parallel with AB=3 Ω.
R_AB=(6×3)/(6+3)=2 Ω.
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