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Current through 3 Ω resistor is 0.8 ampere, then potential drop through 4 Ω resistor is

Asked in CBSE AIPMT 1993 · Series and parallel combinations

• (1) 9.6 V
• (2) 2.6 V
• (3) 4.8 V
• (4) 1.2 V

Step-by-step solution

Why the other options are wrong

• (1) Gives the 6 Ω resistor twice the current of the 3 Ω (1.6 A) instead of half, so the total is taken as 2.4 A.
• (2) No single slip gives 2.6 V; the 4 Ω resistor carries at least the 0.8 A of the 3 Ω branch, so its drop is at least 3.2 V.
• (4) 1.2 is the total current in amperes; it still has to be multiplied by 4 Ω.

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