Consider that an electron is revolving in an excited state of Hydrogen atom with velocity √25.6×10⁵ m s⁻¹. The radius of the orbit is x×10⁻⁹ m. The value of x is : [Take the mass of electron to be 9×10⁻³¹ kg, charge of electron =-1.6×10⁻¹⁹ C and 1/(4πε₀)=9×10⁹ N m² C⁻²]

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(4) 1. The Coulomb force provides the centripetal force: (mv²)/r=(ke²)/(r²), so r=(ke²)/(mv²). ke²=9×10⁹×2.56×10⁻³⁸=2.304×10⁻²⁸. mv²=9×10⁻³¹×25.6×10¹⁰=2.304×10⁻¹⁹. r=1.0×10⁻⁹ m, so x=1.

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