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A step-up transformer is connected to an ac mains supply of 220 V to operate at 11000 V, 88 watt. The current in the secondary circuit, ignoring the power loss in the transformer, is

Asked in NEET 2024 Re · Transformers

Answer: (1) 8 mA

Step-by-step solution

An ideal transformer conserves power, so the 88 W is the power in the secondary as well.

Iₛ=P/(Vₛ)=(88)/(11000)=8×10⁻³ A=8 mA.

The step-up ratio of 50 raises the voltage by 50 and lowers the current by the same factor: the

primary carries (88)/(220)=0.4 A, and (0.4)/(50)=8 mA, which agrees.

Why the other options are wrong

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