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Asked in NEET 2021 · Transformers
An ideal transformer delivers the same power on both sides, so the primary draws 44 W.
Iₚ=P/(Vₚ)=(44)/(220)=0.2 A.
As a check, the secondary carries (44)/(11)=4 A, and the turns ratio of
(220)/(11)=20 divides that to 4/(20)=0.2 A.
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