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In a Young's double slit experiment, the path difference, at a certain point on the screen, between two interfering waves is 1/8th of wavelength. The ratio of the intensity at this point to that at the centre of a bright fringe is close to

Asked in JEE Main 11th Jan 1st Shift 2019 · Intensity and coherent sources

Answer: (3) 0.85

Step-by-step solution

Phase difference φ = (2π)/8 = π/4.

I/(I₀) = cos²φ/2 = cos²π/8.

= (1+cos 45°)/2 = (1+0.707)/2 ≈ 0.85.

Why the other options are wrong

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