In a Young's double slit experiment with light of wavelength λ the separation of slits is d and distance of screen is D such that D d λ. If the fringe width is β, the distance from point of maximum intensity to the point where intensity falls to half of maximum intensity on either side is

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(2) β/4. I = I₀ cos²φ/2; half intensity needs cos²φ/2 = 1/2, so φ = π/2. Path difference λ/4. A path difference of λ corresponds to a distance β, so y = β/4.

In a Young's double slit experiment with light of wavelength λ the separation of slits is d and distance of screen is D such that D d λ. If the fringe width is β, the distance from point of maximum intensity to the point where intensity falls to half of maximum intensity on either side is

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