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It is found that if a neutron suffers an elastic collinear collision with deuterium at rest, fractional loss of its energy is p_d; while for its similar collision with carbon nucleus at rest, fractional loss of energy is p_c. The values of p_d and p_c are respectively

Asked in JEE Main 2018 · Energy transfer in elastic collisions

Answer: (1) (0.89, 0.28)

Step-by-step solution

Fraction transferred: (4m₁m₂)/((m₁+m₂)²).

Deuterium (m₂=2m₁): 8/9=0.89. Carbon (m₂=12m₁): (48)/(169)=0.28.

Why the other options are wrong

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