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Asked in JEE Main Online 2015 · Velocity exchange and mass ratios
Identical beads exchange velocities in elastic collisions, so the motion passes from bead to bead as if one bead travelled the free length of the rod.
The beads occupy n×2r of the rod, leaving a free path L-2nr; a round trip takes (2(L-2nr))/v.
Each hit gives a support impulse 2mv: F=(2mv)/(2(L-2nr)/v)=(mv²)/(L-2nr).
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