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Asked in JEE Main 12th Jan 1st Shift 2019 · Velocity exchange and mass ratios
For small angles the speed at the bottom is proportional to the angle: v₀∝θ₀ before, v₁∝θ₁ after.
Elastic collision with M at rest: v₁=(m-M)/(m+M)v₀. The bob bounces back, so v₁ is reversed and M>m: (θ₁)/(θ₀)=(M-m)/(M+m).
Cross-multiplying: M(θ₀-θ₁)=m(θ₀+θ₁), so M=m((θ₀+θ₁)/(θ₀-θ₁)), larger than m as a rebound requires.
(The book's key prints the inverted ratio, which would make M<m and could not send the bob back.)
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