Practice portal › Work, Energy and Power › Work Done by Gravity, Friction and Contact Forces
Asked in JEE Main 5th April 2nd Shift 2026 · Work done by friction
Given: m=1 kg, incline 30°, assembly rises vertically at v=4 m/s for t=2 s.
The block is at rest relative to the incline, so static friction balances the down-slope component of weight: f=mg sin 30°=5 N, acting up the slope.
Displacement of the block is vertical: d=vt=8 m.
Angle between friction (up the 30° slope) and the vertical displacement is 60°.
W=fd cos 60°=5×8×1/2=20 J.
Reading this solution needs no sign-in. You only sign in to practise against the clock and keep your progress.
Practise this with a timer