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A block of mass 100 kg slides over a distance of 10 m on a horizontal surface. If the co-efficient of friction between the surfaces is 0.4, then the work done against friction (in J) is

Asked in JEE Main 29th Jan 1st Shift 2024 · Work done by friction

Answer: (2) 4000

Step-by-step solution

Given: m=100 kg, d=10 m, μ=0.4, g=10 m/s².

f=μ mg=0.4×100×10=400 N.

Work against friction =fd=400×10=4000 J.

Why the other options are wrong

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