A simple pendulum is being used to determine the value of gravitational acceleration g at a certain place. The length of the pendulum is 25.0 cm and a stop watch with 1 s resolution measures the time taken for 40 oscillations to be 50 s. The accuracy in g is

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(3) 4.40%. Given: L=25.0 cm, so Δ L=0.1 cm; 40 oscillations in 50 s with a 1 s watch. Idea: g=(4π²L)/(T²), and the count of oscillations divides T and Δ T alike, so (Δ T)/T=1/(50). Length: (0.1)/(25.0)=0.4%. Time: 2×1/(50)=4%. Total: 0.4%+4%=4.4%.

A simple pendulum is being used to determine the value of gravitational acceleration g at a certain place. The length of the pendulum is 25.0 cm and a stop watch with 1 s resolution measures the time taken for 40 oscillations to be 50 s. The accuracy in g is

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