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Asked in JEE Main 2015 · Error in g from a pendulum experiment
Given: L=20.0 cm with Δ L=1 mm; 100 oscillations in 90 s with a 1 s watch.
Length: (Δ L)/L=(0.1)/(20.0)=0.5%.
Time: 2(Δ T)/T=2×1/(90)=2.22%.
Total: 0.5%+2.22%=2.72%, which to the nearest option is 3%.
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