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Heat energy of 184 kJ is given to ice of mass 600 g at -12 °C. The specific heat of ice is 2222.3 J kg⁻¹ ° C⁻¹ and the latent heat of ice is 336 kJ kg⁻¹. A. Final temperature of the system will be 0 °C. B. Final temperature of the system will be greater than 0 °C. C. The final system will have a mixture of ice and water in the ratio of 5:1. D. The final system will have a mixture of ice and water in the ratio of 1:5. E. The final system will have water only. Choose the correct answer from the options given below:

Asked in JEE Main 29th Jan 2nd Shift 2023 · Latent heat and change of state

Answer: (1) A and D only

Step-by-step solution

Given: m=0.6 kg at -12 °C, c_ice=2222.3 J kg⁻¹ ° C⁻¹, L=336 kJ kg⁻¹, Q=184 kJ.

Sensible heat first: warming the ice to 0 °C takes 0.6×2222.3×12=16.0 kJ, leaving 184-16=168 kJ.

Melting all of it would take 0.6×336=201.6 kJ, which is more than is left, so only part of the ice melts.

Mass melted =(168)/(336)=0.5 kg=500 g; the remaining 100 g stays as ice.

With ice still present the temperature stays at 0 °C, and ice : water =100:500=1:5 — statements A and D.

Why the other options are wrong

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