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Asked in JEE Main 29th Jan 2nd Shift 2023 · Latent heat and change of state
Given: m=0.6 kg at -12 °C, c_ice=2222.3 J kg⁻¹ ° C⁻¹, L=336 kJ kg⁻¹, Q=184 kJ.
Sensible heat first: warming the ice to 0 °C takes 0.6×2222.3×12=16.0 kJ, leaving 184-16=168 kJ.
Melting all of it would take 0.6×336=201.6 kJ, which is more than is left, so only part of the ice melts.
Mass melted =(168)/(336)=0.5 kg=500 g; the remaining 100 g stays as ice.
With ice still present the temperature stays at 0 °C, and ice : water =100:500=1:5 — statements A and D.
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