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A copper block of mass 5.0 kg is heated to a temperature of 500 °C and is placed on a large ice block. What is the maximum amount of ice that can melt? (Specific heat of copper =0.39 J g⁻¹ ° C⁻¹ and latent heat of fusion of water =335 J g⁻¹)

Asked in JEE Main 25th June 2nd Shift 2022 · Latent heat and change of state

Answer: (3) 2.9 kg

Step-by-step solution

Given: m_Cu=5.0 kg=5000 g, c=0.39 J g⁻¹ ° C⁻¹, L=335 J g⁻¹.

Idea: the ice block is large, so it stays at 0 °C and the copper gives up all the heat it can, cooling the full 500 °C down to 0 °C.

Heat released: Q=m_CucΔ T=5000×0.39×500=9.75×10⁵ J.

All of it goes into latent heat, since the melt water stays at 0 °C: m_ice=Q/L=(9.75×10⁵)/(335).

m_ice=2910 g≈2.9 kg.

Why the other options are wrong

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