Practice portal › Thermodynamics › Work Done in a Thermodynamic Process
Asked in JEE Main 10th April 2nd Shift 2019 · Work from a Stated P-V Law
T=(PV)/R=(P₀V)/R[1-1/2((V₀)/V)²].
At V=V₀: T₁=(P₀V₀)/R(1-1/2)=(P₀V₀)/(2R).
At V=2V₀: T₂=(2P₀V₀)/R(1-1/8)=(7P₀V₀)/(4R).
Δ T=(7P₀V₀)/(4R)-(2P₀V₀)/(4R)=5/4(P₀V₀)/R.
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