Practice portal › Electromagnetic Induction › Self-Inductance

In a fluorescent lamp choke (a small transformer), 100 V of reverse voltage is produced when the choke current changes uniformly from 0.25 A to 0 A in a duration of 0.025 ms. The self-inductance of the choke (in mH) is estimated to be _____.

Asked in JEE Main 9th Jan 1st Shift 2020 · Self-inductance and self-induced EMF

Answer: 10

Step-by-step solution

ε=L(Δ I)/(Δ t)⇒100=L×(0.25)/(0.025×10⁻³).

L=(100×0.025×10⁻³)/(0.25)=10⁻² H =10 mH.

More Self-Inductance questionsAll Self-Inductance questions →

Reading this solution needs no sign-in. You only sign in to practise against the clock and keep your progress.

Practise this with a timer