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When the current in a coil changes from 5 A to 2 A in 0.1 s, an average voltage of 50 V is produced. The self-inductance of the coil is

Asked in JEE Main Online 2015 · Self-inductance and self-induced EMF

Answer: (2) 1.67 H

Step-by-step solution

L=(ε Δ t)/(Δ I)=(50×0.1)/3=1.67 H.

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