Practice portal › Electromagnetic Induction › Self-Inductance
Asked in JEE Main 25th Feb 1st Shift 2021 · Energy stored in an inductor
V=L(dI)/(dt)⇒3t=2(dI)/(dt), so I=(3t²)/4.
At t=4 s, I=12 A.
U=1/2LI²=1/2×2×144=144 J.
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