Inductance of a coil with 10⁴ turns is 10 mH and it is connected to a dc source of 10 V with internal resistance 10 Ω. The energy density in the inductor when the current reaches of its maximum value is απ × J/m³. The value of α is _. (μ₀ = 4π × 10⁻⁷ T m/A)

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Accepted Answer

20. Iₘₐₓ=(10)/(10)=1 A, and at I=(Iₘₐₓ)/e the stored energy is 1/2LI²=1/2×10⁻²× e⁻² J. Dividing by the volume of the winding and using u=(B²)/(2μ₀) with B=μ₀nI gives u=(20π)/(e²) J m⁻³. So α=20.

Inductance of a coil with 10⁴ turns is 10 mH and it is connected to a dc source of 10 V with internal resistance 10 Ω. The energy density in the inductor when the current reaches of its maximum value is απ × J/m³. The value of α is _____. (μ₀ = 4π × 10⁻⁷ T m/A)

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