The magnetic flux through the loop increases according to the relation φB(t) = 10t² + 20t, where φB is in milliwebers and t is in seconds. The magnitude of current through R = 2 Ω resistor at t = 5 s is mA.

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60. φ_B=10t²+20t in milliweber, so (dφ_B)/(dt)=(20t+20) mWb s⁻¹. At t=5 s that is 120 mWb s⁻¹=0.12 V. I=(0.12)/2=0.06 A =60 mA.

The magnetic flux through the loop increases according to the relation φB(t) = 10t² + 20t, where φB is in milliwebers and t is in seconds. The magnitude of current through R = 2 Ω resistor at t = 5 s is _____ mA.

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