Magnetic flux (in weber) in a closed circuit of resistance 20 Ω varies with time t(s) as φ = 8t² – 9t + 5. The magnitude of the induced current at t = 0.25 s will be mA.

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Accepted Answer

250. (dφ)/(dt)=16t-9. At t=0.25: 4-9=-5 Wb s⁻¹, so |ε|=5 V. I=5/(20)=0.25 A =250 mA.

Magnetic flux (in weber) in a closed circuit of resistance 20 Ω varies with time t(s) as φ = 8t² – 9t + 5. The magnitude of the induced current at t = 0.25 s will be _____ mA.

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