Practice portal › Rotational Motion › Moment of Inertia
Asked in JEE Main 6th April 1st Shift 2023 · Standard bodies and axis theorems
In metres: R=0.1 m, and each centre is (0.4)/2=0.2 m from the axis.
Each sphere: 2/5mR²+md²=2/5(2)(0.01)+(2)(0.04).
=0.008+0.08=0.088 kg m².
Two spheres: I=0.176 kg m².
Written as asked: 176×10⁻³ kg m².
Notice that the shift term is ten times the sphere's own term here, which is why the spheres can almost, but not quite, be treated as points.
Reading this solution needs no sign-in. You only sign in to practise against the clock and keep your progress.
Practise this with a timer