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Asked in JEE Main 6th April 2nd Shift 2023 · Radius of gyration and numericals
Radius of gyration is defined by I=Mk², so k²=I/M.
Ring about the perpendicular axis through its centre: I=MRᵣ², so k²=Rᵣ².
Solid sphere about a diameter: I=2/5MRₛ², so k²=2/5Rₛ².
Setting the two equal: Rᵣ²=2/5Rₛ².
(Rᵣ)/(Rₛ)=√2/5, so x=5.
The masses never appear — radius of gyration is a statement about shape alone.
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