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Asked in JEE Main 9th Jan 1st Shift 2020 · Wires in accelerating and rotating systems
Given: m=10 kg, L=0.3 m, σ_b=4.8×10⁷ N m⁻², A=10⁻² cm²=10⁻⁶ m².
In a space station the body is in free fall, so weight plays no part and the tension alone provides the centripetal force.
The wire breaks at Tₘₐₓ=σ_b A=4.8×10⁷×10⁻⁶=48 N.
Tₘₐₓ=mLωₘₐₓ², so ωₘₐₓ²=(48)/(10×0.3)=16 rad² s⁻².
ωₘₐₓ=4 rad s⁻¹.
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