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Asked in JEE Main 5th April 1st Shift 2026 · Breaking stress and maximum load
Given: breaking stress σ=12×10⁸ N m⁻², A₁=0.008 cm²=8×10⁻⁷ m², A₂=0.004 cm²=4×10⁻⁷ m².
The lower wire carries the 10 kg block and the pan load m; the upper wire carries that plus the 30 kg block.
Lower wire, area A₂: σ A₂=12×10⁸×4×10⁻⁷=480 N, so 10+m≤48, giving m≤38 kg.
Upper wire, area A₁: σ A₁=960 N, so 30+10+m≤96, giving m≤56 kg.
The smaller limit decides, so the maximum added mass is 38 kg.
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